When do exceptions in Java arise in code sequences?

89    Asked by FelicaLaplaca in Java , Asked on Jun 26, 2024

 I am currently engaged in a particular task related to developing a Java-based application that processes a list of integers read from a file. During this particular process, the application performs several things such as reading the file, parsing the content, operations related to division, and outputting results. However, 9while testing my application I encountered several issues which are following:

  • This file data.txt does not exist or is accessible.

  • Some lines in the file may contain nonnumber values.

  • There could be a division by zero if any integer is followed by a zero. 

How can I solve these above issues and explain the types of exceptions that arise at each step of the process? 

Answered by David Piper

Reading the file

Exception (File Not Found Exception)

Handling ( you can use a try-catch block to catch a File Not Found Error. It will provide a message that would indicate that the file is missing and possibly prompt the user to provide a correct path.)

Try {
    BufferedReader reader = new BufferedReader(new FileReader(“data.txt”));
} catch (FileNotFoundException e) {
    System.out.println(“File not found: “ + e.getMessage());
    // Prompt user for a new file or exit
}

Parsing the content

Exception (NumberFormatException)

Handling ( you can wrap the parsing logic in a try-catch block to catch the NumberFormatException. If an invalid line is encountered, then try to skip it and continue with the next line, logging the issue.)

Try {
    Int number = Integer.parseInt(line);
} catch (NumberFormatException e) {
    System.out.println(“Invalid number format: “ + e.getMessage());
    // Skip this line or handle it appropriately
}

Division operations

Exception ( Arithmetic Exception)
Handling ( you should check if the divisor is zero before performing the division. If it is, then you can handle the scenario by skipping the division or even logging an error.)
Try {
    If (nextNumber == 0) {
        Throw new ArithmeticException(“Division by zero”);
    }    Int result = currentNumber / nextNumber;
} catch (ArithmeticException e) {
    System.out.println(“Error in division: “ + e.getMessage());
    // Handle the zero division case
}
Outputting the results
Exception
Unlikely to the cause exception unless involving complex operations. General exceptions may be applied to catch unforeseen errors.
Try {
    System.out.println(“Result: “ + result);
} catch (Exception e) {
    System.out.println(“Unexpected error: “ + e.getMessage());
    // General handling
}

By handling this exception effectively, you can ensure that your particular Java-based application gracefully manages the potential errors and can maintain robust execution.

Here is also a java based example given below:-

Import java.io.*;
Import java.util.*;
Public class ExceptionHandlingExample {
    Public static void main(String[] args) {
        List numbers = new ArrayList<>();
        // Step 1: Reading the file
        Try (BufferedReader reader = new BufferedReader(new FileReader(“data.txt”))) {
            String line;
            While ((line = reader.readLine()) != null) {
                Try {
                    // Step 2: Parsing the content
                    Int number = Integer.parseInt(line.trim());
                    Numbers.add(number);
                } catch (NumberFormatException e) {
                    System.out.println(“Invalid number format: “ + e.getMessage());
                }
            }
        } catch (FileNotFoundException e) {
            System.out.println(“File not found: “ + e.getMessage());
            Return;
        } catch (IOException e) {
            System.out.println(“Error reading file: “ + e.getMessage());
            Return;
        }
        // Step 3: Division operation
        For (int I = 0; I < numbers xss=removed xss=removed xss=removed xss=removed xss=removed>


Your Answer