Group by and Count in Python

91    Asked by Dadhijaraj in Python , Asked on Sep 25, 2024

For me the grouping is not working properly, I have mentioned my code and the result I require from it, I am trying to get results of the group by and count in python.

My Code:

#!/usr/bin/env python
counts = {}
logfile = open("/tmp/test.out", "r")
for line in logfile:
    if line.startswith("20") in line:
        seq = line.strip()
        substr = seq[0:13]
        if substr not in counts:
            counts[substr] = 0
            counts[substr] += 1
            for substr, count in counts.items():
                print(count,substr)

The result that I require as output:

6 2019-06-17T00
13 2019-06-17T01
9 2019-06-17T02
7 2019-06-17T03
6 2019-06-17T04


Answered by Chris EVANS

There is a small issue in this program which is counts[substr] += 1 is indented too much, For Count with respect to Group in Python it should be indented in such a way that it would increment every single time a substring is found.


Updated Code:

for line in logfile:
    if line.startswith("20") in line:
        seq = line.strip()
        substr = seq[0:13]
        if substr not in counts:
            counts[substr] = 0
        # Un-indented below
        counts[substr] += 1

# Print output only after loop completes

for substr, count in counts.items():
    print(count,substr)
Output would be:
6 2019-06-17T00
13 2019-06-17T01
9 2019-06-17T02
7 2019-06-17T03
6 2019-06-17T04


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