How can I use the “getcssvalue” method for styling an element on a web page?

226    Asked by AadityaSrivastva in QA Testing , Asked on Apr 4, 2024

I am currently engaged in a particular task that is related to verifying the stylings of a specific element on a web page by using the selenium’s web driver “GetCSSValue” method. How can I approach this particular task using “getcssvalue” and validate the stylings? 

 In the context of selenium, you can verify the background color of a button with a custom class by using the selenium’s WebDriver “getcssvalue” method. Here are the steps given:-

Identify the button elements

Firstly, you would need to use the Selenium WebDriver to locate the button elements on the web page by using its class name or any other locator.

Retrieve the background color property

Now you can use the “getcssvalue” method for retrieving the value of the background color CSS property.

Assert the background color

Now you can compare the retrieved background color value with the expected RGB value to validate the stylings of the button.

Here is the example given of coding snippet in Java by using selenium WebDriver:-

Import org.openqa.selenium.By;
Import org.openqa.selenium.WebDriver;
Import org.openqa.selenium.WebElement;
Import org.openqa.selenium.chrome.ChromeDriver;
Public class ButtonStyleVerification {
    Public static void main(String[] args) {
        // Set up ChromeDriver path
        System.setProperty(“webdriver.chrome.driver”, “/path/to/chromedriver”);
        // Initialize ChromeDriver
        WebDriver driver = new ChromeDriver();
        Try {
            // Navigate to the web page
            Driver.get(https://example.com/page);
            // Identify the button element using its custom class name
            WebElement button = driver.findElement(By.className(“custom-button-class”));
            // Retrieve the background color CSS property value
            String backgroundColor = button.getCssValue(“background-color”);
            // Assert the background color against the expected RGB value
            String expectedBackgroundColor = “rgb(255, 0, 0)”; // Example RGB value
            If (backgroundColor.equals(expectedBackgroundColor)) {
                System.out.println(“Button background color is as expected.”);
            } else {
                System.out.println(“Button background color is not as expected.”);
            }
        } catch (Exception e) {
            System.err.println(“An error occurred: “ + e.getMessage());
        } finally {
            // Close the browser
            Driver.quit();
        }
    }
}
Here is the example given by using python programming language:-
From selenium import webdriver
From selenium.webdriver.common.by import By
# Set up ChromeDriver path
Chrome_driver_path = “/path/to/chromedriver”
Driver = webdriver.Chrome(chrome_driver_path)
Try:
    # Navigate to the web page
    Driver.get(https://example.com/page)
    # Identify the button element using its custom class name
    Button = driver.find_element(By.CLASS_NAME, “custom-button-class”)
    # Retrieve the background color CSS property value
    Background_color = button.value_of_css_property(“background-color”)
    # Assert the background color against the expected RGB value
    Expected_background_color = “rgb(255, 0, 0)” # Example RGB value
    If background_color == expected_background_color:
        Print(“Button background color is as expected.”)
    Else:
        Print(“Button background color is not as expected.”)
Except Exception as e:
    Print(“An error occurred:”, e)
Finally:
    # Close the browser
    Driver.quit()


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