The following script to find sql server orphaned users from the Brent Ozar Unlimited site iterates through all databases and lists the orphaned users by database, along with the drop command to remove them. There may be a neater/newer way of handling this but this appears to function correctly on 2005-2012.
DECLARE @SQL nvarchar(2000) DECLARE @name nvarchar(128) DECLARE @database_id int SET NOCOUNT ON; IF NOT EXISTS (SELECT name FROM tempdb.sys.tables WHERE name like '%#orphan_users%') BEGIN CREATE TABLE #orphan_users ( database_name nvarchar(128) NOT NULL, [user_name] nvarchar(128) NOT NULL, drop_command_text nvarchar(200) NOT NULL ) END CREATE TABLE #databases ( database_id int NOT NULL , database_name nvarchar(128) NOT NULL , processed bit NOT NULL ) INSERT #databases ( database_id , database_name , processed ) SELECT database_id , name , 0 FROM master.sys.databases
WHERE name NOT IN ('master' , 'tempdb' , 'msdb' , 'distribution' , 'model') WHILE (SELECT COUNT(processed) FROM #databases WHERE processed = 0) > 0 BEGIN SELECT TOP 1 @name = database_name, @database_id = database_id FROM #databases WHERE processed = 0 ORDER BY database_id SELECT @SQL = 'USE [' + @name + ']; INSERT INTO #orphan_users (database_name, user_name, drop_command_text) SELECT DB_NAME() , u.name , ' + '''' + 'USE [' + @name + ']; ' + 'DROP USER [' + '''' + ' + u.name + ' + '''' + '] ' + '''' + ' FROM master..syslogins l RIGHT JOIN sysusers u ON l.sid = u.sid WHERE l.sid IS NULL AND issqlrole <> 1 AND isapprole <> 1 AND ( u.name <> ' + '''' + 'INFORMATION_SCHEMA' + '''' + ' AND u.name <> ' + '''' + 'guest' + '''' + ' AND u.name <> ' + '''' + 'dbo' + '''' + ' AND u.name <> ' + '''' + 'sys' + '''' + ' AND u.name <> ' + '''' + 'system_function_schema' + '''' + ')' PRINT @SQL; EXEC sys.sp_executesql @SQL UPDATE #databases SET processed = 1 WHERE database_id = @database_id; END SELECT database_name , [user_name] , drop_command_text FROM #orphan_users ORDER BY [database_name] , [user_name]; DROP TABLE #databases; DROP TABLE #orphan_users; SET NOCOUNT OFF;